• Let us model the poop rule as a predicate keep that maps the set of real world objects to {true, false} and a function poopy that maps the set of real world objects to the set of real world objects with poop on them.

    For all x, keep(poopy(x)) = keep(poopy(poopy(x))), thus we can say that poopy is idempotent under keep.

    Further, poopy is injective because there exist distinct x and y such that keep(poopy(x)) ≠ keep(poopy(y)). The proof by example is that you would keep a poopy million dollar bill, but you would not keep a poopy poop.

    • BluesF@lemmy.world
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      6 months ago

      Your model is lacking in one area - poopy() has an inverse poopwash() where for some set of poopy objects Y, poopwash maps Y to a subset of the set of real world objects, but there exists a set of poopy objects Z for which poopwash maps Z to a subset of poopy objects.

      My initial instinct was to suggest that for all z in Z, keep(z) = false, however I believe your million dollar example runs counter to this. Nonetheless, I suspect there is a useful subset of Z, let’s say S, for which we can say, for all s in S, keep(s) = false.

  • samus12345@lemmy.world
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    6 months ago

    The problem with this method is that it puts far more importance on what the object is made of rather than how useful it is to keep around.

    • Dasus@lemmy.world
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      6 months ago

      Day 1 on using this method and I’ve tossed away all my electronics and food, sitting in an empty apartment with a ton of linen.

  • ted@sh.itjust.works
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    6 months ago

    Joke’s on you, I have too much climate anxiety to throw anything out. I practically wash my toilet paper rather than flushing it.

  • xantoxis@lemmy.world
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    6 months ago

    By this logic, get rid of all your food and clothing. You can’t get poop stains out of most clothing and obviously you’re not going to risk eating food that had poop on it.

    Also, go ahead and keep your litter box tools forever.